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4324213100140 = 225593664587373
BaseRepresentation
bin111110111011001111001…
…011111000111001101100
3120022101112211211122210221
4332323033023320321230
51031321442023201030
613110303245541124
7624262013614243
oct76731713707154
916271484748727
104324213100140
11141798562142a
1259a08a2747a4
13254a0511661b
1410d41610d95a
1577739200e7a
hex3eecf2f8e6c

4324213100140 has 24 divisors (see below), whose sum is σ = 9234760182480. Its totient is φ = 1700368540608.

The previous prime is 4324213100107. The next prime is 4324213100299. The reversal of 4324213100140 is 410013124234.

It is a super-3 number, since 3×43242131001403 (a number of 39 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1832292507 + ... + 1832294866.

It is an arithmetic number, because the mean of its divisors is an integer number (384781674270).

Almost surely, 24324213100140 is an apocalyptic number.

It is an amenable number.

4324213100140 is an abundant number, since it is smaller than the sum of its proper divisors (4910547082340).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4324213100140 is a wasteful number, since it uses less digits than its factorization.

4324213100140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3664587441 (or 3664587439 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 4324213100140 its reverse (410013124234), we get a palindrome (4734226224374).

The spelling of 4324213100140 in words is "four trillion, three hundred twenty-four billion, two hundred thirteen million, one hundred thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 59 118 236 295 590 1180 3664587373 7329174746 14658349492 18322936865 36645873730 73291747460 216210655007 432421310014 864842620028 1081053275035 2162106550070 4324213100140