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43243122134141 is a prime number
BaseRepresentation
bin10011101010100010100101…
…11011110000110001111101
312200010000001112101100122022
421311101102323300301331
521131443403231243031
6231545341022525525
712052132610251406
oct1165212273606175
9180100045340568
1043243122134141
111286233a10a636
124a249821368a5
131b18a69273a27
14a96d9a57a9ad
154eecbd53897b
hex275452ef0c7d

43243122134141 has 2 divisors, whose sum is σ = 43243122134142. Its totient is φ = 43243122134140.

The previous prime is 43243122134119. The next prime is 43243122134239. The reversal of 43243122134141 is 14143122134234.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 32221857544900 + 11021264589241 = 5676430^2 + 3319829^2 .

It is a cyclic number.

It is not a de Polignac number, because 43243122134141 - 210 = 43243122133117 is a prime.

It is a super-2 number, since 2×432431221341412 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43243122134101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21621561067070 + 21621561067071.

It is an arithmetic number, because the mean of its divisors is an integer number (21621561067071).

Almost surely, 243243122134141 is an apocalyptic number.

It is an amenable number.

43243122134141 is a deficient number, since it is larger than the sum of its proper divisors (1).

43243122134141 is an equidigital number, since it uses as much as digits as its factorization.

43243122134141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 55296, while the sum is 35.

Adding to 43243122134141 its reverse (14143122134234), we get a palindrome (57386244268375).

The spelling of 43243122134141 in words is "forty-three trillion, two hundred forty-three billion, one hundred twenty-two million, one hundred thirty-four thousand, one hundred forty-one".