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432645041531249 is a prime number
BaseRepresentation
bin110001001011111010000011…
…0000000111010100101110001
32002201212110110211020122022022
41202113310012000322211301
5423201424021112444444
64132054215505521225
7160062400310356361
oct14227640600724561
92081773424218268
10432645041531249
11115943805a03118
1240635611043215
13157543385714b1
1478ba1bb6c89a1
1535041551469ee
hex1897d0603a971

432645041531249 has 2 divisors, whose sum is σ = 432645041531250. Its totient is φ = 432645041531248.

The previous prime is 432645041531189. The next prime is 432645041531251. The reversal of 432645041531249 is 942135140546234.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 241148847145024 + 191496194386225 = 15528968^2 + 13838215^2 .

It is a cyclic number.

It is not a de Polignac number, because 432645041531249 - 28 = 432645041530993 is a prime.

Together with 432645041531251, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 432645041531249.

It is not a weakly prime, because it can be changed into another prime (432645041530249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216322520765624 + 216322520765625.

It is an arithmetic number, because the mean of its divisors is an integer number (216322520765625).

Almost surely, 2432645041531249 is an apocalyptic number.

It is an amenable number.

432645041531249 is a deficient number, since it is larger than the sum of its proper divisors (1).

432645041531249 is an equidigital number, since it uses as much as digits as its factorization.

432645041531249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12441600, while the sum is 53.

The spelling of 432645041531249 in words is "four hundred thirty-two trillion, six hundred forty-five billion, forty-one million, five hundred thirty-one thousand, two hundred forty-nine".