Base | Representation |
---|---|
bin | 111110111101100010001… |
… | …000010001100110001111 |
3 | 120022121220122202001012201 |
4 | 332331202020101212033 |
5 | 1031342014132402341 |
6 | 13111352033542331 |
7 | 624410060423434 |
oct | 76754210214617 |
9 | 16277818661181 |
10 | 4326678403471 |
11 | 1418a301872a6 |
12 | 59a657a149a7 |
13 | 255008ab80a8 |
14 | 10d5ab6cbb8b |
15 | 77830876331 |
hex | 3ef6221198f |
4326678403471 has 4 divisors (see below), whose sum is σ = 4352586657552. Its totient is φ = 4300770149392.
The previous prime is 4326678403417. The next prime is 4326678403477. The reversal of 4326678403471 is 1743048766234.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4326678403471 is a prime.
It is a super-3 number, since 3×43266784034713 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4326678403477) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12954126790 + ... + 12954127123.
It is an arithmetic number, because the mean of its divisors is an integer number (1088146664388).
Almost surely, 24326678403471 is an apocalyptic number.
4326678403471 is a deficient number, since it is larger than the sum of its proper divisors (25908254081).
4326678403471 is a wasteful number, since it uses less digits than its factorization.
4326678403471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25908254080.
The product of its (nonzero) digits is 16257024, while the sum is 55.
The spelling of 4326678403471 in words is "four trillion, three hundred twenty-six billion, six hundred seventy-eight million, four hundred three thousand, four hundred seventy-one".
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