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433054501981 is a prime number
BaseRepresentation
bin1100100110101000000…
…11110100110001011101
31112101210022110001100221
412103110003310301131
524043343423030411
6530535324521341
743200331350313
oct6232403646135
91471708401327
10433054501981
11157725a81a32
126bb190b0251
1331ab578b25a
1416d621600b3
15b3e8780071
hex64d40f4c5d

433054501981 has 2 divisors, whose sum is σ = 433054501982. Its totient is φ = 433054501980.

The previous prime is 433054501907. The next prime is 433054502011. The reversal of 433054501981 is 189105450334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 370308760900 + 62745741081 = 608530^2 + 250491^2 .

It is a cyclic number.

It is not a de Polignac number, because 433054501981 - 215 = 433054469213 is a prime.

It is a super-2 number, since 2×4330545019812 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (433054505981) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216527250990 + 216527250991.

It is an arithmetic number, because the mean of its divisors is an integer number (216527250991).

Almost surely, 2433054501981 is an apocalyptic number.

It is an amenable number.

433054501981 is a deficient number, since it is larger than the sum of its proper divisors (1).

433054501981 is an equidigital number, since it uses as much as digits as its factorization.

433054501981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 43.

The spelling of 433054501981 in words is "four hundred thirty-three billion, fifty-four million, five hundred one thousand, nine hundred eighty-one".