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43310053 is a prime number
BaseRepresentation
bin1010010100110…
…1101111100101
310000111101020001
42211031233211
542041410203
64144141301
71034062243
oct245155745
9100441201
1043310053
11224a1536
1212607831
138c85367
145a75793
153c0791d
hex294dbe5

43310053 has 2 divisors, whose sum is σ = 43310054. Its totient is φ = 43310052.

The previous prime is 43310039. The next prime is 43310107. The reversal of 43310053 is 35001334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38912644 + 4397409 = 6238^2 + 2097^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43310053 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 43310053.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43310353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21655026 + 21655027.

It is an arithmetic number, because the mean of its divisors is an integer number (21655027).

Almost surely, 243310053 is an apocalyptic number.

It is an amenable number.

43310053 is a deficient number, since it is larger than the sum of its proper divisors (1).

43310053 is an equidigital number, since it uses as much as digits as its factorization.

43310053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 19.

The square root of 43310053 is about 6581.0373802312. The cubic root of 43310053 is about 351.1798360379.

Adding to 43310053 its reverse (35001334), we get a palindrome (78311387).

The spelling of 43310053 in words is "forty-three million, three hundred ten thousand, fifty-three".