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4331041314221 is a prime number
BaseRepresentation
bin111111000001100110001…
…011011101010110101101
3120100001011201022212121202
4333001212023131112231
51031424433034023341
613113353010135245
7624623145516026
oct77014613352655
916301151285552
104331041314221
11141a869a03766
1259b474b81525
1325555296339b
1410d8a2d0dc4d
15779d88d579b
hex3f0662dd5ad

4331041314221 has 2 divisors, whose sum is σ = 4331041314222. Its totient is φ = 4331041314220.

The previous prime is 4331041314137. The next prime is 4331041314241. The reversal of 4331041314221 is 1224131401334.

4331041314221 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2168344600900 + 2162696713321 = 1472530^2 + 1470611^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4331041314221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4331041314241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165520657110 + 2165520657111.

It is an arithmetic number, because the mean of its divisors is an integer number (2165520657111).

Almost surely, 24331041314221 is an apocalyptic number.

It is an amenable number.

4331041314221 is a deficient number, since it is larger than the sum of its proper divisors (1).

4331041314221 is an equidigital number, since it uses as much as digits as its factorization.

4331041314221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 4331041314221 its reverse (1224131401334), we get a palindrome (5555172715555).

The spelling of 4331041314221 in words is "four trillion, three hundred thirty-one billion, forty-one million, three hundred fourteen thousand, two hundred twenty-one".