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43311031123 is a prime number
BaseRepresentation
bin101000010101100010…
…011110001101010011
311010210102100100022211
4220111202132031103
51202200110443443
631521413412551
73062200455523
oct502542361523
9133712310284
1043311031123
1117405a477a8
12848893a157
134113027889
14214c219683
1511d751819d
hexa1589e353

43311031123 has 2 divisors, whose sum is σ = 43311031124. Its totient is φ = 43311031122.

The previous prime is 43311031109. The next prime is 43311031163. The reversal of 43311031123 is 32113011334.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 43311031123 - 25 = 43311031091 is a prime.

It is a super-2 number, since 2×433110311232 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43311031094 and 43311031103.

It is not a weakly prime, because it can be changed into another prime (43311031163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21655515561 + 21655515562.

It is an arithmetic number, because the mean of its divisors is an integer number (21655515562).

Almost surely, 243311031123 is an apocalyptic number.

43311031123 is a deficient number, since it is larger than the sum of its proper divisors (1).

43311031123 is an equidigital number, since it uses as much as digits as its factorization.

43311031123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 43311031123 its reverse (32113011334), we get a palindrome (75424042457).

The spelling of 43311031123 in words is "forty-three billion, three hundred eleven million, thirty-one thousand, one hundred twenty-three".