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43311100111361 is a prime number
BaseRepresentation
bin10011101100100001001101…
…01111001010101000000001
312200100111112000221101201022
421312100212233022220001
521134102113112030421
6232040502242515225
712060060302444045
oct1166204657125001
9180314460841638
1043311100111361
1112889152992aa5
124a35b93965b15
131b222b0802ca4
14a9a3a8804025
1550194b3867ab
hex276426bcaa01

43311100111361 has 2 divisors, whose sum is σ = 43311100111362. Its totient is φ = 43311100111360.

The previous prime is 43311100111309. The next prime is 43311100111399. The reversal of 43311100111361 is 16311100111334.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35307542260225 + 8003557851136 = 5942015^2 + 2829056^2 .

It is a cyclic number.

It is not a de Polignac number, because 43311100111361 - 26 = 43311100111297 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 43311100111361.

It is not a weakly prime, because it can be changed into another prime (43311100101361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21655550055680 + 21655550055681.

It is an arithmetic number, because the mean of its divisors is an integer number (21655550055681).

Almost surely, 243311100111361 is an apocalyptic number.

It is an amenable number.

43311100111361 is a deficient number, since it is larger than the sum of its proper divisors (1).

43311100111361 is an equidigital number, since it uses as much as digits as its factorization.

43311100111361 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 26.

Adding to 43311100111361 its reverse (16311100111334), we get a palindrome (59622200222695).

The spelling of 43311100111361 in words is "forty-three trillion, three hundred eleven billion, one hundred million, one hundred eleven thousand, three hundred sixty-one".