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433121241013 is a prime number
BaseRepresentation
bin1100100110110000000…
…10011010011110110101
31112101221222000202002221
412103120002122132311
524044013014203023
6530550111202341
743202101542616
oct6233002323665
91471858022087
10433121241013
1115775a715a5a
126bb375163b1
1331ac65576c6
1416d6ad73c0d
15b3ee56485d
hex64d809a7b5

433121241013 has 2 divisors, whose sum is σ = 433121241014. Its totient is φ = 433121241012.

The previous prime is 433121240941. The next prime is 433121241023. The reversal of 433121241013 is 310142121334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 219434159844 + 213687081169 = 468438^2 + 462263^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-433121241013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (433121241023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216560620506 + 216560620507.

It is an arithmetic number, because the mean of its divisors is an integer number (216560620507).

Almost surely, 2433121241013 is an apocalyptic number.

It is an amenable number.

433121241013 is a deficient number, since it is larger than the sum of its proper divisors (1).

433121241013 is an equidigital number, since it uses as much as digits as its factorization.

433121241013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 433121241013 its reverse (310142121334), we get a palindrome (743263362347).

The spelling of 433121241013 in words is "four hundred thirty-three billion, one hundred twenty-one million, two hundred forty-one thousand, thirteen".