Base | Representation |
---|---|
bin | 111111000001110001000… |
… | …100101111110110100111 |
3 | 120100001122110021120112212 |
4 | 333001301010233312213 |
5 | 1031430321332314414 |
6 | 13113423100034035 |
7 | 624630525304625 |
oct | 77016104576647 |
9 | 16301573246485 |
10 | 4331224104359 |
11 | 141a953101699 |
12 | 59b50623291b |
13 | 2555817a3229 |
14 | 10d8bd2d2515 |
15 | 779e999083e |
hex | 3f07112fda7 |
4331224104359 has 2 divisors, whose sum is σ = 4331224104360. Its totient is φ = 4331224104358.
The previous prime is 4331224104271. The next prime is 4331224104371. The reversal of 4331224104359 is 9534014221334.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4331224104359 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4331224104659) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165612052179 + 2165612052180.
It is an arithmetic number, because the mean of its divisors is an integer number (2165612052180).
Almost surely, 24331224104359 is an apocalyptic number.
4331224104359 is a deficient number, since it is larger than the sum of its proper divisors (1).
4331224104359 is an equidigital number, since it uses as much as digits as its factorization.
4331224104359 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 41.
The spelling of 4331224104359 in words is "four trillion, three hundred thirty-one billion, two hundred twenty-four million, one hundred four thousand, three hundred fifty-nine".
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