Base | Representation |
---|---|
bin | 111111000001110001011… |
… | …100001010000101001101 |
3 | 120100001122212211100120121 |
4 | 333001301130022011031 |
5 | 1031430324420203401 |
6 | 13113423435344541 |
7 | 624630631414201 |
oct | 77016134120515 |
9 | 16301585740517 |
10 | 4331230241101 |
11 | 141a956613285 |
12 | 59b5082b2151 |
13 | 255582b4153a |
14 | 10d8c004cb01 |
15 | 779ea2a3ca1 |
hex | 3f07170a14d |
4331230241101 has 2 divisors, whose sum is σ = 4331230241102. Its totient is φ = 4331230241100.
The previous prime is 4331230241083. The next prime is 4331230241141. The reversal of 4331230241101 is 1011420321334.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4288999580100 + 42230661001 = 2070990^2 + 205501^2 .
It is a cyclic number.
It is not a de Polignac number, because 4331230241101 - 25 = 4331230241069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4331230241141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165615120550 + 2165615120551.
It is an arithmetic number, because the mean of its divisors is an integer number (2165615120551).
Almost surely, 24331230241101 is an apocalyptic number.
It is an amenable number.
4331230241101 is a deficient number, since it is larger than the sum of its proper divisors (1).
4331230241101 is an equidigital number, since it uses as much as digits as its factorization.
4331230241101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 4331230241101 its reverse (1011420321334), we get a palindrome (5342650562435).
The spelling of 4331230241101 in words is "four trillion, three hundred thirty-one billion, two hundred thirty million, two hundred forty-one thousand, one hundred one".
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