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43312315141 is a prime number
BaseRepresentation
bin101000010101100111…
…010111101100000101
311010210111202120200001
4220111213113230011
51202200423041031
631521501121301
73062214414154
oct502547275405
9133714676601
1043312315141
1117406744477
128489259231
134113387154
14214c47159b
1511d76bd861
hexa159d7b05

43312315141 has 2 divisors, whose sum is σ = 43312315142. Its totient is φ = 43312315140.

The previous prime is 43312315121. The next prime is 43312315147. The reversal of 43312315141 is 14151321334.

43312315141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43296870241 + 15444900 = 208079^2 + 3930^2 .

It is a cyclic number.

It is not a de Polignac number, because 43312315141 - 29 = 43312314629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43312315147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21656157570 + 21656157571.

It is an arithmetic number, because the mean of its divisors is an integer number (21656157571).

Almost surely, 243312315141 is an apocalyptic number.

It is an amenable number.

43312315141 is a deficient number, since it is larger than the sum of its proper divisors (1).

43312315141 is an equidigital number, since it uses as much as digits as its factorization.

43312315141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4320, while the sum is 28.

Adding to 43312315141 its reverse (14151321334), we get a palindrome (57463636475).

The spelling of 43312315141 in words is "forty-three billion, three hundred twelve million, three hundred fifteen thousand, one hundred forty-one".