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4331255140337 is a prime number
BaseRepresentation
bin111111000001110010111…
…011001000111111110001
3120100001201121200100220112
4333001302323020333301
51031430402303442322
613113430125151105
7624631353146546
oct77016273107761
916301647610815
104331255140337
11141a96967a464
1259b5146bb495
1325558804b908
1410d8c3490bcd
15779ec5715e2
hex3f072ec8ff1

4331255140337 has 2 divisors, whose sum is σ = 4331255140338. Its totient is φ = 4331255140336.

The previous prime is 4331255140313. The next prime is 4331255140339. The reversal of 4331255140337 is 7330415521334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2500648846336 + 1830606294001 = 1581344^2 + 1352999^2 .

It is a cyclic number.

It is not a de Polignac number, because 4331255140337 - 28 = 4331255140081 is a prime.

Together with 4331255140339, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4331255140294 and 4331255140303.

It is not a weakly prime, because it can be changed into another prime (4331255140339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165627570168 + 2165627570169.

It is an arithmetic number, because the mean of its divisors is an integer number (2165627570169).

Almost surely, 24331255140337 is an apocalyptic number.

It is an amenable number.

4331255140337 is a deficient number, since it is larger than the sum of its proper divisors (1).

4331255140337 is an equidigital number, since it uses as much as digits as its factorization.

4331255140337 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 453600, while the sum is 41.

The spelling of 4331255140337 in words is "four trillion, three hundred thirty-one billion, two hundred fifty-five million, one hundred forty thousand, three hundred thirty-seven".