Base | Representation |
---|---|
bin | 1000000100010100… |
… | …11011111110001101 |
3 | 102011212000200122101 |
4 | 10002022123332031 |
5 | 32332300221431 |
6 | 1553441515101 |
7 | 212222040406 |
oct | 40212337615 |
9 | 12155020571 |
10 | 4331257741 |
11 | 1922978058 |
12 | a0a642a91 |
13 | 540444b05 |
14 | 2d13429ad |
15 | 1a53aa961 |
hex | 10229bf8d |
4331257741 has 2 divisors, whose sum is σ = 4331257742. Its totient is φ = 4331257740.
The previous prime is 4331257729. The next prime is 4331257747. The reversal of 4331257741 is 1477521334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4223700100 + 107557641 = 64990^2 + 10371^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4331257741 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4331257741.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4331257747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165628870 + 2165628871.
It is an arithmetic number, because the mean of its divisors is an integer number (2165628871).
Almost surely, 24331257741 is an apocalyptic number.
It is an amenable number.
4331257741 is a deficient number, since it is larger than the sum of its proper divisors (1).
4331257741 is an equidigital number, since it uses as much as digits as its factorization.
4331257741 is an evil number, because the sum of its binary digits is even.
The product of its digits is 70560, while the sum is 37.
The square root of 4331257741 is about 65812.2917166695. The cubic root of 4331257741 is about 1630.0640747893.
The spelling of 4331257741 in words is "four billion, three hundred thirty-one million, two hundred fifty-seven thousand, seven hundred forty-one".
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