43313234342113 has 4 divisors (see below), whose sum is σ = 45196418443968. Its totient is φ = 41430050240260.

The previous prime is 43313234342093. The next prime is 43313234342177. The reversal of 43313234342113 is 31124343231334.

43313234342113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43313234342113 - 2³⁷ = 43175795388641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43313234342713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 941592050893 + ... + 941592050938.

It is an arithmetic number, because the mean of its divisors is an integer number (11299104610992).

Almost surely, 2^{43313234342113} is an apocalyptic number.

It is an amenable number.

43313234342113 is a deficient number, since it is larger than the sum of its proper divisors (1883184101855).

43313234342113 is a wasteful number, since it uses less digits than its factorization.

43313234342113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1883184101854.

The product of its digits is 186624, while the sum is 37.

Adding to 43313234342113 its reverse (31124343231334), we get a palindrome (74437577573447).

The spelling of 43313234342113 in words is "forty-three trillion, three hundred thirteen billion, two hundred thirty-four million, three hundred forty-two thousand, one hundred thirteen".