433134011133 has 12 divisors (see below), whose sum is σ = 625896896508. Its totient is φ = 288636524160.

The previous prime is 433134011117. The next prime is 433134011137. The reversal of 433134011133 is 331110431334.

It can be written as a sum of positive squares in 2 ways, for example, as 337001148324 + 96132862809 = 580518^2 + 310053^2 .

It is not a de Polignac number, because 433134011133 - 2⁴ = 433134011117 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 433134011097 and 433134011106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (433134011137) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9933978 + ... + 9977483.

It is an arithmetic number, because the mean of its divisors is an integer number (52158074709).

Almost surely, 2^433134011133 is an apocalyptic number.

It is an amenable number.

433134011133 is a deficient number, since it is larger than the sum of its proper divisors (192762885375).

433134011133 is a wasteful number, since it uses less digits than its factorization.

433134011133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19913884 (or 19913881 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 433134011133 its reverse (331110431334), we get a palindrome (764244442467).

The spelling of 433134011133 in words is "four hundred thirty-three billion, one hundred thirty-four million, eleven thousand, one hundred thirty-three".