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4331344045 = 57131944677
BaseRepresentation
bin1000000100010101…
…10001000010101101
3102011212012002000211
410002022301002231
532332311002140
61553443422421
7212222550130
oct40212610255
912155162024
104331344045
111922a26986
12a0a684a11
13540475192
142d1366217
151a53c62ea
hex1022b10ad

4331344045 has 16 divisors (see below), whose sum is σ = 5985479808. Its totient is φ = 2947389120.

The previous prime is 4331344037. The next prime is 4331344051. The reversal of 4331344045 is 5404431334.

It is not a de Polignac number, because 4331344045 - 23 = 4331344037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4331343998 and 4331344016.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 467754 + ... + 476923.

It is an arithmetic number, because the mean of its divisors is an integer number (374092488).

Almost surely, 24331344045 is an apocalyptic number.

It is an amenable number.

4331344045 is a deficient number, since it is larger than the sum of its proper divisors (1654135763).

4331344045 is a wasteful number, since it uses less digits than its factorization.

4331344045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 944820.

The product of its (nonzero) digits is 34560, while the sum is 31.

The square root of 4331344045 is about 65812.9473963900. The cubic root of 4331344045 is about 1630.0749015225.

Adding to 4331344045 its reverse (5404431334), we get a palindrome (9735775379).

The spelling of 4331344045 in words is "four billion, three hundred thirty-one million, three hundred forty-four thousand, forty-five".

Divisors: 1 5 7 35 131 655 917 4585 944677 4723385 6612739 33063695 123752687 618763435 866268809 4331344045