Base | Representation |
---|---|
bin | 101000010101101101… |
… | …111101100101000001 |
3 | 11010210122000101010021 |
4 | 220111231331211001 |
5 | 1202201343340301 |
6 | 31522002133441 |
7 | 3062235202222 |
oct | 502555754501 |
9 | 133718011107 |
10 | 43314043201 |
11 | 17407714820 |
12 | 8489951281 |
13 | 4113840880 |
14 | 214c7a1249 |
15 | 11d79108a1 |
hex | a15b7d941 |
43314043201 has 16 divisors (see below), whose sum is σ = 51110635968. Its totient is φ = 36187300800.
The previous prime is 43314043183. The next prime is 43314043277. The reversal of 43314043201 is 10234041334.
43314043201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 43314043201 - 227 = 43179825473 is a prime.
It is a super-2 number, since 2×433140432012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43314043901) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 634710 + ... + 699631.
It is an arithmetic number, because the mean of its divisors is an integer number (3194414748).
Almost surely, 243314043201 is an apocalyptic number.
It is an amenable number.
43314043201 is a deficient number, since it is larger than the sum of its proper divisors (7796592767).
43314043201 is a wasteful number, since it uses less digits than its factorization.
43314043201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1334592.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 43314043201 its reverse (10234041334), we get a palindrome (53548084535).
The spelling of 43314043201 in words is "forty-three billion, three hundred fourteen million, forty-three thousand, two hundred one".
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