Base | Representation |
---|---|
bin | 1100100110110010010… |
… | …11110100011111111101 |
3 | 1112102000022020101122121 |
4 | 12103121023310133331 |
5 | 24044032430442333 |
6 | 530552035442541 |
7 | 43202424240112 |
oct | 6233113643775 |
9 | 1472008211577 |
10 | 433140484093 |
11 | 15776a569629 |
12 | 6bb41a56451 |
13 | 31aca534445 |
14 | 16d6d742909 |
15 | b4010b632d |
hex | 64d92f47fd |
433140484093 has 2 divisors, whose sum is σ = 433140484094. Its totient is φ = 433140484092.
The previous prime is 433140483989. The next prime is 433140484099. The reversal of 433140484093 is 390484041334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 298813103044 + 134327381049 = 546638^2 + 366507^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-433140484093 is a prime.
It is a super-2 number, since 2×4331404840932 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (433140484099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216570242046 + 216570242047.
It is an arithmetic number, because the mean of its divisors is an integer number (216570242047).
Almost surely, 2433140484093 is an apocalyptic number.
It is an amenable number.
433140484093 is a deficient number, since it is larger than the sum of its proper divisors (1).
433140484093 is an equidigital number, since it uses as much as digits as its factorization.
433140484093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 497664, while the sum is 43.
The spelling of 433140484093 in words is "four hundred thirty-three billion, one hundred forty million, four hundred eighty-four thousand, ninety-three".
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