Base | Representation |
---|---|
bin | 111111000001111100010… |
… | …010110110110001101001 |
3 | 120100002010120111112220121 |
4 | 333001330102312301221 |
5 | 1031431213030231410 |
6 | 13113453502523241 |
7 | 624635302344106 |
oct | 77017422666151 |
9 | 16302116445817 |
10 | 4331412352105 |
11 | 141aa3a397a43 |
12 | 59b559296521 |
13 | 2555b17a4227 |
14 | 10d8da2d5aad |
15 | 77a0b2779da |
hex | 3f07c4b6c69 |
4331412352105 has 16 divisors (see below), whose sum is σ = 5213497766400. Its totient is φ = 3454598054592.
The previous prime is 4331412352063. The next prime is 4331412352129. The reversal of 4331412352105 is 5012532141334.
It is a cyclic number.
It is not a de Polignac number, because 4331412352105 - 229 = 4330875481193 is a prime.
It is a super-2 number, since 2×43314123521052 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9919492 + ... + 10346938.
It is an arithmetic number, because the mean of its divisors is an integer number (325843610400).
Almost surely, 24331412352105 is an apocalyptic number.
It is an amenable number.
4331412352105 is a deficient number, since it is larger than the sum of its proper divisors (882085414295).
4331412352105 is a wasteful number, since it uses less digits than its factorization.
4331412352105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 433608.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 4331412352105 its reverse (5012532141334), we get a palindrome (9343944493439).
The spelling of 4331412352105 in words is "four trillion, three hundred thirty-one billion, four hundred twelve million, three hundred fifty-two thousand, one hundred five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.123 sec. • engine limits •