Search a number
-
+
433141431913 is a prime number
BaseRepresentation
bin1100100110110010011…
…11011011111001101001
31112102000101000112211001
412103121033123321221
524044033201310123
6530552112035001
743202435265331
oct6233117337151
91472011015731
10433141431913
11157770056753
126bb42232a61
1331aca7a6998
1416d6d90c0c1
15b4012020ad
hex64d93dbe69

433141431913 has 2 divisors, whose sum is σ = 433141431914. Its totient is φ = 433141431912.

The previous prime is 433141431893. The next prime is 433141432019. The reversal of 433141431913 is 319134141334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 233451316224 + 199690115689 = 483168^2 + 446867^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-433141431913 is a prime.

It is a super-2 number, since 2×4331414319132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (433141435913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216570715956 + 216570715957.

It is an arithmetic number, because the mean of its divisors is an integer number (216570715957).

Almost surely, 2433141431913 is an apocalyptic number.

It is an amenable number.

433141431913 is a deficient number, since it is larger than the sum of its proper divisors (1).

433141431913 is an equidigital number, since it uses as much as digits as its factorization.

433141431913 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 46656, while the sum is 37.

The spelling of 433141431913 in words is "four hundred thirty-three billion, one hundred forty-one million, four hundred thirty-one thousand, nine hundred thirteen".