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43314410123989 is a prime number
BaseRepresentation
bin10011101100100111011000…
…00001110111001011010101
312200100211001201022110102121
421312103230001313023111
521134130402442431424
6232042210523535541
712060235314210454
oct1166235401671325
9180324051273377
1043314410123989
111288a5a1346524
124a3675838a5b1
131b226ba4ac844
14a9a600268b9b
15501a91c65ee4
hex2764ec0772d5

43314410123989 has 2 divisors, whose sum is σ = 43314410123990. Its totient is φ = 43314410123988.

The previous prime is 43314410123983. The next prime is 43314410124017. The reversal of 43314410123989 is 98932101441334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31943317992964 + 11371092131025 = 5651842^2 + 3372105^2 .

It is a cyclic number.

It is not a de Polignac number, because 43314410123989 - 243 = 34518317101781 is a prime.

It is a super-2 number, since 2×433144101239892 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43314410123983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21657205061994 + 21657205061995.

It is an arithmetic number, because the mean of its divisors is an integer number (21657205061995).

Almost surely, 243314410123989 is an apocalyptic number.

It is an amenable number.

43314410123989 is a deficient number, since it is larger than the sum of its proper divisors (1).

43314410123989 is an equidigital number, since it uses as much as digits as its factorization.

43314410123989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2239488, while the sum is 52.

The spelling of 43314410123989 in words is "forty-three trillion, three hundred fourteen billion, four hundred ten million, one hundred twenty-three thousand, nine hundred eighty-nine".