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43314431101 = 536121316287
BaseRepresentation
bin101000010101101111…
…011100010001111101
311010210122202002012221
4220111233130101331
51202201443243401
631522014325341
73062241406144
oct502557342175
9133718662187
1043314431101
111740795a1a7
128489ab9851
1341139482b6
14214c86275b
1511d798a7a1
hexa15bdc47d

43314431101 has 16 divisors (see below), whose sum is σ = 44883341568. Its totient is φ = 41774241600.

The previous prime is 43314431077. The next prime is 43314431129. The reversal of 43314431101 is 10113441334.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 43314431101 - 219 = 43313906813 is a prime.

It is a super-2 number, since 2×433144311012 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43314431131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6886380 + ... + 6892666.

It is an arithmetic number, because the mean of its divisors is an integer number (2805208848).

Almost surely, 243314431101 is an apocalyptic number.

It is an amenable number.

43314431101 is a deficient number, since it is larger than the sum of its proper divisors (1568910467).

43314431101 is a wasteful number, since it uses less digits than its factorization.

43314431101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8532.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 43314431101 its reverse (10113441334), we get a palindrome (53427872435).

The spelling of 43314431101 in words is "forty-three billion, three hundred fourteen million, four hundred thirty-one thousand, one hundred one".

Divisors: 1 53 61 2131 3233 6287 112943 129991 333211 383507 6889523 13397597 20325871 710072641 817253417 43314431101