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43315245101053 is a prime number
BaseRepresentation
bin10011101100101000111011…
…10011000010111111111101
312200100220012220110200122001
421312110131303002333331
521134134110221213203
6232042425432222301
712060265103332102
oct1166243563027775
9180326186420561
1043315245101053
111288a98a6a7112
124a3694bb3a991
131b227c148ac03
14a9a67d0daaa9
15501ae01eb91d
hex27651dcc2ffd

43315245101053 has 2 divisors, whose sum is σ = 43315245101054. Its totient is φ = 43315245101052.

The previous prime is 43315245101003. The next prime is 43315245101057. The reversal of 43315245101053 is 35010154251334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43286899001284 + 28346099769 = 6579278^2 + 168363^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43315245101053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43315245101057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21657622550526 + 21657622550527.

It is an arithmetic number, because the mean of its divisors is an integer number (21657622550527).

Almost surely, 243315245101053 is an apocalyptic number.

It is an amenable number.

43315245101053 is a deficient number, since it is larger than the sum of its proper divisors (1).

43315245101053 is an equidigital number, since it uses as much as digits as its factorization.

43315245101053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 37.

Adding to 43315245101053 its reverse (35010154251334), we get a palindrome (78325399352387).

The spelling of 43315245101053 in words is "forty-three trillion, three hundred fifteen billion, two hundred forty-five million, one hundred one thousand, fifty-three".