Base | Representation |
---|---|
bin | 111111000010001101110… |
… | …000110010101000101110 |
3 | 120100002212222221112201001 |
4 | 333002031300302220232 |
5 | 1031432313041142032 |
6 | 13113542532110514 |
7 | 624645461330413 |
oct | 77021560625056 |
9 | 16302788845631 |
10 | 4331705412142 |
11 | 142007a861319 |
12 | 59b61b46543a |
13 | 25562a412234 |
14 | 10d9271c010a |
15 | 77a26d653e7 |
hex | 3f08dc32a2e |
4331705412142 has 8 divisors (see below), whose sum is σ = 6498001590696. Its totient is φ = 2165704881912.
The previous prime is 4331705412101. The next prime is 4331705412143. The reversal of 4331705412142 is 2412145071334.
4331705412142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4331705412143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73875448 + ... + 73934059.
It is an arithmetic number, because the mean of its divisors is an integer number (812250198837).
Almost surely, 24331705412142 is an apocalyptic number.
4331705412142 is a deficient number, since it is larger than the sum of its proper divisors (2166296178554).
4331705412142 is a wasteful number, since it uses less digits than its factorization.
4331705412142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147824162.
The product of its (nonzero) digits is 80640, while the sum is 37.
The spelling of 4331705412142 in words is "four trillion, three hundred thirty-one billion, seven hundred five million, four hundred twelve thousand, one hundred forty-two".
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