Base | Representation |
---|---|
bin | 111111000010100000000… |
… | …110110100100011011111 |
3 | 120100010200110001121210112 |
4 | 333002200012310203133 |
5 | 1031433430333131210 |
6 | 13114033244400235 |
7 | 624656216310254 |
oct | 77024006644337 |
9 | 16303613047715 |
10 | 4332013177055 |
11 | 1420218559693 |
12 | 59b6a654607b |
13 | 2556790cb455 |
14 | 10d95601542b |
15 | 77a43da9d05 |
hex | 3f0a01b48df |
4332013177055 has 16 divisors (see below), whose sum is σ = 5240282826240. Its totient is φ = 3437784428832.
The previous prime is 4332013177049. The next prime is 4332013177109. The reversal of 4332013177055 is 5507713102334.
4332013177055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 4332013177055 - 224 = 4331996399839 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4919885 + ... + 5733174.
It is an arithmetic number, because the mean of its divisors is an integer number (327517676640).
Almost surely, 24332013177055 is an apocalyptic number.
4332013177055 is a deficient number, since it is larger than the sum of its proper divisors (908269649185).
4332013177055 is a wasteful number, since it uses less digits than its factorization.
4332013177055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10653718.
The product of its (nonzero) digits is 264600, while the sum is 41.
Adding to 4332013177055 its reverse (5507713102334), we get a palindrome (9839726279389).
The spelling of 4332013177055 in words is "four trillion, three hundred thirty-two billion, thirteen million, one hundred seventy-seven thousand, fifty-five".
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