Base | Representation |
---|---|
bin | 111111000010100111111… |
… | …101010001010000100101 |
3 | 120100011000121220101020201 |
4 | 333002213331101100211 |
5 | 1031434213043002132 |
6 | 13114054311430501 |
7 | 624662405666554 |
oct | 77024775212045 |
9 | 16304017811221 |
10 | 4332144890917 |
11 | 1420285941218 |
12 | 59b722685431 |
13 | 25569a49704c |
14 | 10d9696ddd9b |
15 | 77a507262e7 |
hex | 3f0a7f51425 |
4332144890917 has 2 divisors, whose sum is σ = 4332144890918. Its totient is φ = 4332144890916.
The previous prime is 4332144890881. The next prime is 4332144890933. The reversal of 4332144890917 is 7190984412334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2770247332836 + 1561897558081 = 1664406^2 + 1249759^2 .
It is a cyclic number.
It is not a de Polignac number, because 4332144890917 - 215 = 4332144858149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4332144890977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166072445458 + 2166072445459.
It is an arithmetic number, because the mean of its divisors is an integer number (2166072445459).
Almost surely, 24332144890917 is an apocalyptic number.
It is an amenable number.
4332144890917 is a deficient number, since it is larger than the sum of its proper divisors (1).
4332144890917 is an equidigital number, since it uses as much as digits as its factorization.
4332144890917 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5225472, while the sum is 55.
The spelling of 4332144890917 in words is "four trillion, three hundred thirty-two billion, one hundred forty-four million, eight hundred ninety thousand, nine hundred seventeen".
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