Base | Representation |
---|---|
bin | 101000010110001100… |
… | …101100100110101011 |
3 | 11010211012011201011101 |
4 | 220112030230212223 |
5 | 1202210424201024 |
6 | 31522450542231 |
7 | 3062363526643 |
oct | 502614544653 |
9 | 133735151141 |
10 | 43322100139 |
11 | 1741121804a |
12 | 8490597977 |
13 | 4115401ba6 |
14 | 214d89b523 |
15 | 11d84a2c44 |
hex | a1632c9ab |
43322100139 has 4 divisors (see below), whose sum is σ = 43435213056. Its totient is φ = 43208987224.
The previous prime is 43322100119. The next prime is 43322100209. The reversal of 43322100139 is 93100122334.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43322100139 is a prime.
It is a super-4 number, since 4×433221001394 (a number of 44 digits) contains 4444 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (43322100119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56555884 + ... + 56556649.
It is an arithmetic number, because the mean of its divisors is an integer number (10858803264).
Almost surely, 243322100139 is an apocalyptic number.
43322100139 is a deficient number, since it is larger than the sum of its proper divisors (113112917).
43322100139 is a wasteful number, since it uses less digits than its factorization.
43322100139 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 113112916.
The product of its (nonzero) digits is 3888, while the sum is 28.
The spelling of 43322100139 in words is "forty-three billion, three hundred twenty-two million, one hundred thousand, one hundred thirty-nine".
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