Base | Representation |
---|---|
bin | 111111000010101100011… |
… | …011111110101001101111 |
3 | 120100011012212022212011121 |
4 | 333002230123332221233 |
5 | 1031434341313100111 |
6 | 13114105554401411 |
7 | 624664310561416 |
oct | 77025433765157 |
9 | 16304185285147 |
10 | 4332220050031 |
11 | 1420314306395 |
12 | 59b743890267 |
13 | 2556acc20bb3 |
14 | 10d9756a647d |
15 | 77a57120871 |
hex | 3f0ac6fea6f |
4332220050031 has 2 divisors, whose sum is σ = 4332220050032. Its totient is φ = 4332220050030.
The previous prime is 4332220049933. The next prime is 4332220050083. The reversal of 4332220050031 is 1300500222334.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4332220050031 - 27 = 4332220049903 is a prime.
It is a super-2 number, since 2×43322200500312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4332220049978 and 4332220050005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4332220051031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166110025015 + 2166110025016.
It is an arithmetic number, because the mean of its divisors is an integer number (2166110025016).
Almost surely, 24332220050031 is an apocalyptic number.
4332220050031 is a deficient number, since it is larger than the sum of its proper divisors (1).
4332220050031 is an equidigital number, since it uses as much as digits as its factorization.
4332220050031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 4332220050031 its reverse (1300500222334), we get a palindrome (5632720272365).
The spelling of 4332220050031 in words is "four trillion, three hundred thirty-two billion, two hundred twenty million, fifty thousand, thirty-one".
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