433222121401 has 4 divisors (see below), whose sum is σ = 433232422992. Its totient is φ = 433211819812.

The previous prime is 433222121399. The next prime is 433222121413. The reversal of 433222121401 is 104121222334.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 104121222334 = 2 ⋅52060611167.

It is a cyclic number.

It is not a de Polignac number, because 433222121401 - 2¹ = 433222121399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (433222121461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5087455 + ... + 5171908.

It is an arithmetic number, because the mean of its divisors is an integer number (108308105748).

Almost surely, 2^433222121401 is an apocalyptic number.

It is an amenable number.

433222121401 is a deficient number, since it is larger than the sum of its proper divisors (10301591).

433222121401 is a wasteful number, since it uses less digits than its factorization.

433222121401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10301590.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 433222121401 its reverse (104121222334), we get a palindrome (537343343735).

The spelling of 433222121401 in words is "four hundred thirty-three billion, two hundred twenty-two million, one hundred twenty-one thousand, four hundred one".