Base | Representation |
---|---|
bin | 101000010110010100… |
… | …000100110001001001 |
3 | 11010211022210222002100 |
4 | 220112110010301021 |
5 | 1202211423042441 |
6 | 31523000224013 |
7 | 3062416133244 |
oct | 502624046111 |
9 | 133738728070 |
10 | 43324034121 |
11 | 17412319085 |
12 | 849116b009 |
13 | 411592b264 |
14 | 214dc4225b |
15 | 11d8735cb6 |
hex | a16504c49 |
43324034121 has 12 divisors (see below), whose sum is σ = 62581109760. Its totient is φ = 28881789720.
The previous prime is 43324034113. The next prime is 43324034147. The reversal of 43324034121 is 12143042334.
43324034121 is a `hidden beast` number, since 4 + 3 + 3 + 240 + 3 + 412 + 1 = 666.
It is not a de Polignac number, because 43324034121 - 23 = 43324034113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (43324034321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 367336 + ... + 470726.
It is an arithmetic number, because the mean of its divisors is an integer number (5215092480).
Almost surely, 243324034121 is an apocalyptic number.
It is an amenable number.
43324034121 is a deficient number, since it is larger than the sum of its proper divisors (19257075639).
43324034121 is a wasteful number, since it uses less digits than its factorization.
43324034121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 149956 (or 149953 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 43324034121 its reverse (12143042334), we get a palindrome (55467076455).
The spelling of 43324034121 in words is "forty-three billion, three hundred twenty-four million, thirty-four thousand, one hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •