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43324034121 = 3246559103391
BaseRepresentation
bin101000010110010100…
…000100110001001001
311010211022210222002100
4220112110010301021
51202211423042441
631523000224013
73062416133244
oct502624046111
9133738728070
1043324034121
1117412319085
12849116b009
13411592b264
14214dc4225b
1511d8735cb6
hexa16504c49

43324034121 has 12 divisors (see below), whose sum is σ = 62581109760. Its totient is φ = 28881789720.

The previous prime is 43324034113. The next prime is 43324034147. The reversal of 43324034121 is 12143042334.

43324034121 is a `hidden beast` number, since 4 + 3 + 3 + 240 + 3 + 412 + 1 = 666.

It is not a de Polignac number, because 43324034121 - 23 = 43324034113 is a prime.

It is not an unprimeable number, because it can be changed into a prime (43324034321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 367336 + ... + 470726.

It is an arithmetic number, because the mean of its divisors is an integer number (5215092480).

Almost surely, 243324034121 is an apocalyptic number.

It is an amenable number.

43324034121 is a deficient number, since it is larger than the sum of its proper divisors (19257075639).

43324034121 is a wasteful number, since it uses less digits than its factorization.

43324034121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149956 (or 149953 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 43324034121 its reverse (12143042334), we get a palindrome (55467076455).

The spelling of 43324034121 in words is "forty-three billion, three hundred twenty-four million, thirty-four thousand, one hundred twenty-one".

Divisors: 1 3 9 46559 103391 139677 310173 419031 930519 4813781569 14441344707 43324034121