Base | Representation |
---|---|
bin | 101000010110010100… |
… | …011000000011011010 |
3 | 11010211022221222110000 |
4 | 220112110120003122 |
5 | 1202211433104424 |
6 | 31523002033430 |
7 | 3062416612452 |
oct | 502624300332 |
9 | 133738858400 |
10 | 43324113114 |
11 | 17412372467 |
12 | 84911a8876 |
13 | 41159581b9 |
14 | 214dc62d62 |
15 | 11d874e3c9 |
hex | a165180da |
43324113114 has 60 divisors (see below), whose sum is σ = 103124603934. Its totient is φ = 13591863936.
The previous prime is 43324113037. The next prime is 43324113169. The reversal of 43324113114 is 41131142334.
43324113114 is a `hidden beast` number, since 4 + 332 + 4 + 11 + 311 + 4 = 666.
It can be written as a sum of positive squares in 3 ways, for example, as 42162462225 + 1161650889 = 205335^2 + 34083^2 .
It is a super-2 number, since 2×433241131142 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 29 ways as a sum of consecutive naturals, for example, 415869 + ... + 509504.
Almost surely, 243324113114 is an apocalyptic number.
43324113114 is an abundant number, since it is smaller than the sum of its proper divisors (59800490820).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
43324113114 is a wasteful number, since it uses less digits than its factorization.
43324113114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 925421 (or 925395 counting only the distinct ones).
The product of its digits is 3456, while the sum is 27.
Adding to 43324113114 its reverse (41131142334), we get a palindrome (84455255448).
The spelling of 43324113114 in words is "forty-three billion, three hundred twenty-four million, one hundred thirteen thousand, one hundred fourteen".
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