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4332413120141 is a prime number
BaseRepresentation
bin111111000010110111111…
…100011110111010001101
3120100011201022121211120102
4333002313330132322031
51031440240224321031
613114141052500445
7625002143624141
oct77026774367215
916304638554512
104332413120141
111420403295867
1259b79847a725
13255710c1cb72
1410d9931a3221
1577a6905b7cb
hex3f0b7f1ee8d

4332413120141 has 2 divisors, whose sum is σ = 4332413120142. Its totient is φ = 4332413120140.

The previous prime is 4332413120111. The next prime is 4332413120177. The reversal of 4332413120141 is 1410213142334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3256689436900 + 1075723683241 = 1804630^2 + 1037171^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4332413120141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4332413120111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166206560070 + 2166206560071.

It is an arithmetic number, because the mean of its divisors is an integer number (2166206560071).

Almost surely, 24332413120141 is an apocalyptic number.

It is an amenable number.

4332413120141 is a deficient number, since it is larger than the sum of its proper divisors (1).

4332413120141 is an equidigital number, since it uses as much as digits as its factorization.

4332413120141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 4332413120141 its reverse (1410213142334), we get a palindrome (5742626262475).

The spelling of 4332413120141 in words is "four trillion, three hundred thirty-two billion, four hundred thirteen million, one hundred twenty thousand, one hundred forty-one".