Base | Representation |
---|---|
bin | 1000000100011110… |
… | …10010110101100001 |
3 | 102011221102101021122 |
4 | 10002033102311201 |
5 | 32333111443131 |
6 | 1553525102025 |
7 | 212235622556 |
oct | 40217226541 |
9 | 12157371248 |
10 | 4332531041 |
11 | 1923667773 |
12 | a0ab57915 |
13 | 54079c547 |
14 | 2d1594a2d |
15 | 1a555cd7b |
hex | 1023d2d61 |
4332531041 has 2 divisors, whose sum is σ = 4332531042. Its totient is φ = 4332531040.
The previous prime is 4332531037. The next prime is 4332531043. The reversal of 4332531041 is 1401352334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3934927441 + 397603600 = 62729^2 + 19940^2 .
It is a cyclic number.
It is not a de Polignac number, because 4332531041 - 22 = 4332531037 is a prime.
Together with 4332531043, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4332531041.
It is not a weakly prime, because it can be changed into another prime (4332531043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2166265520 + 2166265521.
It is an arithmetic number, because the mean of its divisors is an integer number (2166265521).
Almost surely, 24332531041 is an apocalyptic number.
It is an amenable number.
4332531041 is a deficient number, since it is larger than the sum of its proper divisors (1).
4332531041 is an equidigital number, since it uses as much as digits as its factorization.
4332531041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 26.
The square root of 4332531041 is about 65821.9647306277. The cubic root of 4332531041 is about 1630.2237941560.
Adding to 4332531041 its reverse (1401352334), we get a palindrome (5733883375).
The spelling of 4332531041 in words is "four billion, three hundred thirty-two million, five hundred thirty-one thousand, forty-one".
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