Base | Representation |
---|---|
bin | 111111000011000100010… |
… | …010100011010111001110 |
3 | 120100012020202100012211021 |
4 | 333003010102203113032 |
5 | 1031441201234412032 |
6 | 13114213411544354 |
7 | 625010240222206 |
oct | 77030422432716 |
9 | 16305222305737 |
10 | 4332620232142 |
11 | 14204aa196104 |
12 | 59b8358bb0ba |
13 | 255744ac7347 |
14 | 10d9b28b7406 |
15 | 77a7c31d097 |
hex | 3f0c44a35ce |
4332620232142 has 8 divisors (see below), whose sum is σ = 6499026534600. Its totient is φ = 2166278053944.
The previous prime is 4332620232119. The next prime is 4332620232179. The reversal of 4332620232142 is 2412320262334.
4332620232142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 4332620232098 and 4332620232107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15861792 + ... + 16132627.
It is an arithmetic number, because the mean of its divisors is an integer number (812378316825).
Almost surely, 24332620232142 is an apocalyptic number.
4332620232142 is a deficient number, since it is larger than the sum of its proper divisors (2166406302458).
4332620232142 is a wasteful number, since it uses less digits than its factorization.
4332620232142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32062130.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 4332620232142 its reverse (2412320262334), we get a palindrome (6744940494476).
The spelling of 4332620232142 in words is "four trillion, three hundred thirty-two billion, six hundred twenty million, two hundred thirty-two thousand, one hundred forty-two".
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