Base | Representation |
---|---|
bin | 10011101101011000010011… |
… | …01001000100000010101101 |
3 | 12200110022212021120222100101 |
4 | 21312230021221010002231 |
5 | 21140043201221241331 |
6 | 232102233152431101 |
7 | 12062155241613565 |
oct | 1166541151040255 |
9 | 180408767528311 |
10 | 43340676743341 |
11 | 1289a7501503aa |
12 | 4a3b868b48491 |
13 | 1b25015264363 |
14 | a9b9b2923da5 |
15 | 5025ccc33061 |
hex | 276b09a440ad |
43340676743341 has 2 divisors, whose sum is σ = 43340676743342. Its totient is φ = 43340676743340.
The previous prime is 43340676743333. The next prime is 43340676743389. The reversal of 43340676743341 is 14334767604334.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 41093612784900 + 2247063958441 = 6410430^2 + 1499021^2 .
It is a cyclic number.
It is not a de Polignac number, because 43340676743341 - 23 = 43340676743333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43340676743321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21670338371670 + 21670338371671.
It is an arithmetic number, because the mean of its divisors is an integer number (21670338371671).
Almost surely, 243340676743341 is an apocalyptic number.
It is an amenable number.
43340676743341 is a deficient number, since it is larger than the sum of its proper divisors (1).
43340676743341 is an equidigital number, since it uses as much as digits as its factorization.
43340676743341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36578304, while the sum is 55.
The spelling of 43340676743341 in words is "forty-three trillion, three hundred forty billion, six hundred seventy-six million, seven hundred forty-three thousand, three hundred forty-one".
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