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43340676743341 is a prime number
BaseRepresentation
bin10011101101011000010011…
…01001000100000010101101
312200110022212021120222100101
421312230021221010002231
521140043201221241331
6232102233152431101
712062155241613565
oct1166541151040255
9180408767528311
1043340676743341
111289a7501503aa
124a3b868b48491
131b25015264363
14a9b9b2923da5
155025ccc33061
hex276b09a440ad

43340676743341 has 2 divisors, whose sum is σ = 43340676743342. Its totient is φ = 43340676743340.

The previous prime is 43340676743333. The next prime is 43340676743389. The reversal of 43340676743341 is 14334767604334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 41093612784900 + 2247063958441 = 6410430^2 + 1499021^2 .

It is a cyclic number.

It is not a de Polignac number, because 43340676743341 - 23 = 43340676743333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43340676743321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21670338371670 + 21670338371671.

It is an arithmetic number, because the mean of its divisors is an integer number (21670338371671).

Almost surely, 243340676743341 is an apocalyptic number.

It is an amenable number.

43340676743341 is a deficient number, since it is larger than the sum of its proper divisors (1).

43340676743341 is an equidigital number, since it uses as much as digits as its factorization.

43340676743341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36578304, while the sum is 55.

The spelling of 43340676743341 in words is "forty-three trillion, three hundred forty billion, six hundred seventy-six million, seven hundred forty-three thousand, three hundred forty-one".