Base | Representation |
---|---|
bin | 111111000100100101000… |
… | …101101000001100011101 |
3 | 120100100102221012001120201 |
4 | 333010211011220030131 |
5 | 1032003013010442023 |
6 | 13115042503543501 |
7 | 625065420056431 |
oct | 77044505501435 |
9 | 16310387161521 |
10 | 4334244234013 |
11 | 1421162970811 |
12 | 5a000975ab91 |
13 | 2559433b4bb5 |
14 | 10dac84589c1 |
15 | 77b24badbad |
hex | 3f12516831d |
4334244234013 has 4 divisors (see below), whose sum is σ = 4344300485568. Its totient is φ = 4324187982460.
The previous prime is 4334244233953. The next prime is 4334244234029. The reversal of 4334244234013 is 3104324424334.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4334244234013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4334244232013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5028125131 + ... + 5028125992.
It is an arithmetic number, because the mean of its divisors is an integer number (1086075121392).
Almost surely, 24334244234013 is an apocalyptic number.
It is an amenable number.
4334244234013 is a deficient number, since it is larger than the sum of its proper divisors (10056251555).
4334244234013 is a wasteful number, since it uses less digits than its factorization.
4334244234013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10056251554.
The product of its (nonzero) digits is 331776, while the sum is 37.
Adding to 4334244234013 its reverse (3104324424334), we get a palindrome (7438568658347).
The spelling of 4334244234013 in words is "four trillion, three hundred thirty-four billion, two hundred forty-four million, two hundred thirty-four thousand, thirteen".
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