Base | Representation |
---|---|
bin | 111111000100101110100… |
… | …111010010100000001001 |
3 | 120100100212001220201000111 |
4 | 333010232213102200021 |
5 | 1032003324414144001 |
6 | 13115110413234321 |
7 | 625102400363131 |
oct | 77045647224011 |
9 | 16310761821014 |
10 | 4334404053001 |
11 | 14212350aa120 |
12 | 5a00531929a1 |
13 | 25596a541149 |
14 | 10db0177bac1 |
15 | 77b33c2c851 |
hex | 3f12e9d2809 |
4334404053001 has 4 divisors (see below), whose sum is σ = 4728440785104. Its totient is φ = 3940367320900.
The previous prime is 4334404052893. The next prime is 4334404053029. The reversal of 4334404053001 is 1003504044334.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4334404053001 - 213 = 4334404044809 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4334404053041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 197018366035 + ... + 197018366056.
It is an arithmetic number, because the mean of its divisors is an integer number (1182110196276).
Almost surely, 24334404053001 is an apocalyptic number.
It is an amenable number.
4334404053001 is a deficient number, since it is larger than the sum of its proper divisors (394036732103).
4334404053001 is a wasteful number, since it uses less digits than its factorization.
4334404053001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 394036732102.
The product of its (nonzero) digits is 34560, while the sum is 31.
Adding to 4334404053001 its reverse (1003504044334), we get a palindrome (5337908097335).
The spelling of 4334404053001 in words is "four trillion, three hundred thirty-four billion, four hundred four million, fifty-three thousand, one".
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