Base | Representation |
---|---|
bin | 1100100111010110001… |
… | …10110001010010111101 |
3 | 1112102210020222210221011 |
4 | 12103223012301102331 |
5 | 24100141413301031 |
6 | 531041540035221 |
7 | 43213034662366 |
oct | 6235306612275 |
9 | 1472706883834 |
10 | 433441150141 |
11 | 15790425846a |
12 | 70006692b11 |
13 | 31b4790644c |
14 | 16d9b64ab6d |
15 | b41c6a76b1 |
hex | 64eb1b14bd |
433441150141 has 4 divisors (see below), whose sum is σ = 434603191132. Its totient is φ = 432279109152.
The previous prime is 433441150139. The next prime is 433441150159. The reversal of 433441150141 is 141051144334.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 171864139225 + 261577010916 = 414565^2 + 511446^2 .
It is a cyclic number.
It is not a de Polignac number, because 433441150141 - 21 = 433441150139 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (433441150171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 581019936 + ... + 581020681.
It is an arithmetic number, because the mean of its divisors is an integer number (108650797783).
Almost surely, 2433441150141 is an apocalyptic number.
It is an amenable number.
433441150141 is a deficient number, since it is larger than the sum of its proper divisors (1162040991).
433441150141 is a wasteful number, since it uses less digits than its factorization.
433441150141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1162040990.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 433441150141 its reverse (141051144334), we get a palindrome (574492294475).
The spelling of 433441150141 in words is "four hundred thirty-three billion, four hundred forty-one million, one hundred fifty thousand, one hundred forty-one".
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