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433940450413 is a prime number
BaseRepresentation
bin1100101000010001101…
…11011100110001101101
31112111002001111220010211
412110020313130301231
524102202223403123
6531203253502421
743231306653331
oct6241067346155
91474061456124
10433940450413
11158040087118
1270125941a11
1331bc71a4bb2
1417007a9d7c1
15b44b43340d
hex6508ddcc6d

433940450413 has 2 divisors, whose sum is σ = 433940450414. Its totient is φ = 433940450412.

The previous prime is 433940450393. The next prime is 433940450423. The reversal of 433940450413 is 314054049334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 418404572964 + 15535877449 = 646842^2 + 124643^2 .

It is a cyclic number.

It is not a de Polignac number, because 433940450413 - 25 = 433940450381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (433940450423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216970225206 + 216970225207.

It is an arithmetic number, because the mean of its divisors is an integer number (216970225207).

Almost surely, 2433940450413 is an apocalyptic number.

It is an amenable number.

433940450413 is a deficient number, since it is larger than the sum of its proper divisors (1).

433940450413 is an equidigital number, since it uses as much as digits as its factorization.

433940450413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 40.

Adding to 433940450413 its reverse (314054049334), we get a palindrome (747994499747).

The spelling of 433940450413 in words is "four hundred thirty-three billion, nine hundred forty million, four hundred fifty thousand, four hundred thirteen".