Base | Representation |
---|---|
bin | 1100101000011000110… |
… | …10101010001101101001 |
3 | 1112111020012120221110121 |
4 | 12110030122222031221 |
5 | 24102313000342022 |
6 | 531213222243241 |
7 | 43232632143556 |
oct | 6241432521551 |
9 | 1474205527417 |
10 | 434000012137 |
11 | 15807076878a |
12 | 70141886521 |
13 | 31c0662a513 |
14 | 17011965a2d |
15 | b45179b2c7 |
hex | 650c6aa369 |
434000012137 has 2 divisors, whose sum is σ = 434000012138. Its totient is φ = 434000012136.
The previous prime is 434000012129. The next prime is 434000012161. The reversal of 434000012137 is 731210000434.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 225293571801 + 208706440336 = 474651^2 + 456844^2 .
It is a cyclic number.
It is not a de Polignac number, because 434000012137 - 23 = 434000012129 is a prime.
It is a super-2 number, since 2×4340000121372 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (434000612137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217000006068 + 217000006069.
It is an arithmetic number, because the mean of its divisors is an integer number (217000006069).
Almost surely, 2434000012137 is an apocalyptic number.
It is an amenable number.
434000012137 is a deficient number, since it is larger than the sum of its proper divisors (1).
434000012137 is an equidigital number, since it uses as much as digits as its factorization.
434000012137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
The spelling of 434000012137 in words is "four hundred thirty-four billion, twelve thousand, one hundred thirty-seven".
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