Base | Representation |
---|---|
bin | 111111001001111101010… |
… | …110110110111110111111 |
3 | 120100220100110112010111101 |
4 | 333021331112312332333 |
5 | 1032101330122111333 |
6 | 13121435553033531 |
7 | 625361513166655 |
oct | 77117526667677 |
9 | 16326313463441 |
10 | 4340020113343 |
11 | 1423657234402 |
12 | 5a115bb558a7 |
13 | 256353bcc785 |
14 | 1100b55a6dd5 |
15 | 77d61cc567d |
hex | 3f27d5b6fbf |
4340020113343 has 2 divisors, whose sum is σ = 4340020113344. Its totient is φ = 4340020113342.
The previous prime is 4340020113301. The next prime is 4340020113349. The reversal of 4340020113343 is 3433110200434.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4340020113343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4340020113349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170010056671 + 2170010056672.
It is an arithmetic number, because the mean of its divisors is an integer number (2170010056672).
Almost surely, 24340020113343 is an apocalyptic number.
4340020113343 is a deficient number, since it is larger than the sum of its proper divisors (1).
4340020113343 is an equidigital number, since it uses as much as digits as its factorization.
4340020113343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 4340020113343 its reverse (3433110200434), we get a palindrome (7773130313777).
The spelling of 4340020113343 in words is "four trillion, three hundred forty billion, twenty million, one hundred thirteen thousand, three hundred forty-three".
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