Base | Representation |
---|---|
bin | 1100101000011001001… |
… | …11010000001110000101 |
3 | 1112111020102210200010211 |
4 | 12110030213100032011 |
5 | 24102314322013131 |
6 | 531213421115421 |
7 | 43233002203630 |
oct | 6241447201605 |
9 | 1474212720124 |
10 | 434003313541 |
11 | 158072613116 |
12 | 701429b8b71 |
13 | 31c07215105 |
14 | 17012184c17 |
15 | b451bee5b1 |
hex | 650c9d0385 |
434003313541 has 4 divisors (see below), whose sum is σ = 496003786912. Its totient is φ = 372002840172.
The previous prime is 434003313517. The next prime is 434003313553. The reversal of 434003313541 is 145313300434.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 434003313541 - 217 = 434003182469 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (434003313041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31000236675 + ... + 31000236688.
It is an arithmetic number, because the mean of its divisors is an integer number (124000946728).
Almost surely, 2434003313541 is an apocalyptic number.
It is an amenable number.
434003313541 is a deficient number, since it is larger than the sum of its proper divisors (62000473371).
434003313541 is an equidigital number, since it uses as much as digits as its factorization.
434003313541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62000473370.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 434003313541 its reverse (145313300434), we get a palindrome (579316613975).
The spelling of 434003313541 in words is "four hundred thirty-four billion, three million, three hundred thirteen thousand, five hundred forty-one".
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