43401200113 has 4 divisors (see below), whose sum is σ = 43413020068. Its totient is φ = 43389380160.

The previous prime is 43401200111. The next prime is 43401200131. The reversal of 43401200113 is 31100210434.

43401200113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 15975190449 + 27426009664 = 126393^2 + 165608^2 .

It is a cyclic number.

It is not a de Polignac number, because 43401200113 - 2¹ = 43401200111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43401200111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5904468 + ... + 5911813.

It is an arithmetic number, because the mean of its divisors is an integer number (10853255017).

Almost surely, 2^43401200113 is an apocalyptic number.

It is an amenable number.

43401200113 is a deficient number, since it is larger than the sum of its proper divisors (11819955).

43401200113 is a wasteful number, since it uses less digits than its factorization.

43401200113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11819954.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 43401200113 its reverse (31100210434), we get a palindrome (74501410547).

The spelling of 43401200113 in words is "forty-three billion, four hundred one million, two hundred thousand, one hundred thirteen".