Base | Representation |
---|---|
bin | 110001010101110110110101… |
… | …1010001101101110111000100 |
3 | 2002220201012020010221022222022 |
4 | 1202223231223101231313010 |
5 | 423341330140222101000 |
6 | 4135022335224422312 |
7 | 160263241224016220 |
oct | 14253555321556704 |
9 | 2086635203838868 |
10 | 434012540034500 |
11 | 116320759190899 |
12 | 40816655617998 |
13 | 1582328c77b78b |
14 | 7926467569780 |
15 | 35299dec58585 |
hex | 18abb6b46ddc4 |
434012540034500 has 48 divisors (see below), whose sum is σ = 1083295299934848. Its totient is φ = 148804299439200.
The previous prime is 434012540034499. The next prime is 434012540034551. The reversal of 434012540034500 is 5430045210434.
It is a super-2 number, since 2×4340125400345002 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62001787934 + ... + 62001794933.
It is an arithmetic number, because the mean of its divisors is an integer number (22568652081976).
Almost surely, 2434012540034500 is an apocalyptic number.
It is an amenable number.
434012540034500 is an abundant number, since it is smaller than the sum of its proper divisors (649282759900348).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
434012540034500 is a wasteful number, since it uses less digits than its factorization.
434012540034500 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 124003582893 (or 124003582881 counting only the distinct ones).
The product of its (nonzero) digits is 115200, while the sum is 35.
Adding to 434012540034500 its reverse (5430045210434), we get a palindrome (439442585244934).
The spelling of 434012540034500 in words is "four hundred thirty-four trillion, twelve billion, five hundred forty million, thirty-four thousand, five hundred".
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