Base | Representation |
---|---|
bin | 111111001010000100001… |
… | …101010000000110001001 |
3 | 120100220122110202202202011 |
4 | 333022010031100012021 |
5 | 1032102044032112043 |
6 | 13121455220135521 |
7 | 625364410051222 |
oct | 77120415200611 |
9 | 16326573682664 |
10 | 4340135035273 |
11 | 1423706097a04 |
12 | 5a11925375a1 |
13 | 25637196920b |
14 | 1100c6960249 |
15 | 77d6be2659d |
hex | 3f284350189 |
4340135035273 has 2 divisors, whose sum is σ = 4340135035274. Its totient is φ = 4340135035272.
The previous prime is 4340135035217. The next prime is 4340135035277. The reversal of 4340135035273 is 3725305310434.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3057504039184 + 1282630996089 = 1748572^2 + 1132533^2 .
It is a cyclic number.
It is not a de Polignac number, because 4340135035273 - 29 = 4340135034761 is a prime.
It is not a weakly prime, because it can be changed into another prime (4340135035277) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170067517636 + 2170067517637.
It is an arithmetic number, because the mean of its divisors is an integer number (2170067517637).
Almost surely, 24340135035273 is an apocalyptic number.
It is an amenable number.
4340135035273 is a deficient number, since it is larger than the sum of its proper divisors (1).
4340135035273 is an equidigital number, since it uses as much as digits as its factorization.
4340135035273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 453600, while the sum is 40.
The spelling of 4340135035273 in words is "four trillion, three hundred forty billion, one hundred thirty-five million, thirty-five thousand, two hundred seventy-three".
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