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43402013443111 is a prime number
BaseRepresentation
bin10011101111001010100011…
…00110000000010000100111
312200200012011221102011110111
421313211101212000100213
521142044310420134421
6232150335411033451
712066456232143301
oct1167452146002047
9180605157364414
1043402013443111
1112913766111814
124a4b72659b887
131b2aa3b908b4b
14aa0950b2c971
15503ebc9c4ee1
hex277951980427

43402013443111 has 2 divisors, whose sum is σ = 43402013443112. Its totient is φ = 43402013443110.

The previous prime is 43402013443097. The next prime is 43402013443147. The reversal of 43402013443111 is 11134431020434.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 43402013443111 - 235 = 43367653704743 is a prime.

It is a super-2 number, since 2×434020134431112 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43402013449111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21701006721555 + 21701006721556.

It is an arithmetic number, because the mean of its divisors is an integer number (21701006721556).

Almost surely, 243402013443111 is an apocalyptic number.

43402013443111 is a deficient number, since it is larger than the sum of its proper divisors (1).

43402013443111 is an equidigital number, since it uses as much as digits as its factorization.

43402013443111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 43402013443111 its reverse (11134431020434), we get a palindrome (54536444463545).

The spelling of 43402013443111 in words is "forty-three trillion, four hundred two billion, thirteen million, four hundred forty-three thousand, one hundred eleven".