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4340213434441 is a prime number
BaseRepresentation
bin111111001010001000111…
…000010100100001001001
3120100220211221021212012001
4333022020320110201021
51032102224114400231
613121511100351001
7625366351326223
oct77121070244111
916326757255161
104340213434441
111423746375405
125a11b4845461
13256384c88a61
141100d312b413
1577d73c60b61
hex3f288e14849

4340213434441 has 2 divisors, whose sum is σ = 4340213434442. Its totient is φ = 4340213434440.

The previous prime is 4340213434423. The next prime is 4340213434481. The reversal of 4340213434441 is 1444343120434.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2571789542400 + 1768423892041 = 1603680^2 + 1329821^2 .

It is a cyclic number.

It is not a de Polignac number, because 4340213434441 - 211 = 4340213432393 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4340213434441.

It is not a weakly prime, because it can be changed into another prime (4340213434481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170106717220 + 2170106717221.

It is an arithmetic number, because the mean of its divisors is an integer number (2170106717221).

Almost surely, 24340213434441 is an apocalyptic number.

It is an amenable number.

4340213434441 is a deficient number, since it is larger than the sum of its proper divisors (1).

4340213434441 is an equidigital number, since it uses as much as digits as its factorization.

4340213434441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 221184, while the sum is 37.

Adding to 4340213434441 its reverse (1444343120434), we get a palindrome (5784556554875).

The spelling of 4340213434441 in words is "four trillion, three hundred forty billion, two hundred thirteen million, four hundred thirty-four thousand, four hundred forty-one".