Base | Representation |
---|---|
bin | 111111001010001000111… |
… | …010101000110111111111 |
3 | 120100220211222102201202100 |
4 | 333022020322220313333 |
5 | 1032102224243321421 |
6 | 13121511121400143 |
7 | 625366356436653 |
oct | 77121072506777 |
9 | 16326758381670 |
10 | 4340214042111 |
11 | 142374674aa12 |
12 | 5a11b4a99053 |
13 | 25638513c51c |
14 | 1100d3248a63 |
15 | 77d73d30c26 |
hex | 3f288ea8dff |
4340214042111 has 12 divisors (see below), whose sum is σ = 6357496626000. Its totient is φ = 2852722844160.
The previous prime is 4340214042067. The next prime is 4340214042121. The reversal of 4340214042111 is 1112404120434.
4340214042111 is a `hidden beast` number, since 4 + 3 + 40 + 2 + 1 + 404 + 211 + 1 = 666.
It is not a de Polignac number, because 4340214042111 - 27 = 4340214041983 is a prime.
It is a super-4 number, since 4×43402140421114 (a number of 52 digits) contains 4444 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4340214042121) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3396097986 + ... + 3396099263.
It is an arithmetic number, because the mean of its divisors is an integer number (529791385500).
Almost surely, 24340214042111 is an apocalyptic number.
4340214042111 is a deficient number, since it is larger than the sum of its proper divisors (2017282583889).
4340214042111 is a wasteful number, since it uses less digits than its factorization.
4340214042111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6792197326 (or 6792197323 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 4340214042111 its reverse (1112404120434), we get a palindrome (5452618162545).
The spelling of 4340214042111 in words is "four trillion, three hundred forty billion, two hundred fourteen million, forty-two thousand, one hundred eleven".
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